Answer:
Magnitude = 10.44
Direction = 73.3°
Explanation:
Since the directions are perpendicular you could think of the birth flying north as moving through the "y" and the crosswind moving through the "x" in a coordinate system.
The birth is flying north so "y" is positive and the crosswind is blowing easterly so its moving to the right, then "x" is also positive.
Then you could assume that the vector you need to calculate starts in the origin (0,0) and the second point is (3,10)
Magnitude = [tex]\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}} \\= \sqrt{10^{2}+3^{2}} \\= 10.44[/tex]
Direction :
[tex]tan(\theta) = \frac{(y_{2}-y_{1})}{(x_{2}-x_{1})} = \frac{10}{3} \\\theta = tan^{-1}(\frac{10}{3}) \\\theta = 73.3 \°[/tex]
