Answer:
Measure of largest angle of the triangular patch is 86.5°
Step-by-step explanation:
As shown in the figure attached.
ABC is the triangular park which is boarded by walking paths.
Longest side (path) of the triangle BC = 90 feet
Smallest side (path) of the triangle AC = 53 feet
Measure of angle given opposite to the smallest side = 53°
We have to calculate the measure of the angle opposite to the longest side.
We apply sine rule in ΔABC
[tex]\frac{sinB}{AC}=\frac{sinA}{BC}[/tex]
Now we put the values
[tex]\frac{sin36}{53}=\frac{sinA}{90}[/tex]
[tex]\frac{0.588}{53}=\frac{sinA}{90}[/tex]
Now we cross multiply
90×0.588 = 53×sinA
sinA = [tex]\frac{52.90}{53}[/tex]
sinA = 0.998
A = [tex]sin^{-1}(0.998)[/tex]
= 86.4768° ≈ 86.5°
Therefore, ∠A = 86.5° is the answer.
∠A = 90°