Answer :

[tex]\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-18})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-(-18)}{2-(-4)}\implies \cfrac{6+18}{2+4}\implies \cfrac{24}{6}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-18)=4[x-(-4)]\implies y+18=4(x+4) \\\\\\ y+18=4x+16\implies y=4x-2[/tex]

[tex]\bf \rule{34em}{0.25pt}\\\\\\\\ (\stackrel{x_1}{7}~,~\stackrel{y_1}{2})~\hspace{10em} slope = m\implies -10 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-10(x-7) \\\\\\ y-2=-10x+70\implies y=-10x+72[/tex]

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