DUE TONIGHT!!! ALGEBRA
Someone draw me a graph that includes the following
I have to submit a graph showing these clearly


Show me On a graph, the quadratic function
f(x) = 3x2 + 6x - 9 would look like a
parabola opening upwards due to the positive coefficient of x?.
The vertex of the parabola is at (−1, −12).
The y-intercept is at (0, -9).
The zeros (x-intercepts) are at x = 1 and
2= -3.
Here's how you can graph it:
Plot the vertex at (-1, - 12).
Plot the y-intercept at (0, -9).
Plot the zeros at x = 1 and x = −3.
Draw a smooth parabolic curve passing through these points.
This will give you a good representation of
the quadratic function f(x) = 3x7 +6x-9