The height h in feet of an object shot straight up with initial velocity v in feet per second is given by h = −16t2 + vt + c, where c is the initial height of the object above the ground. A model rocket is shot vertically up from a height of 6 feet above the ground with an initial velocity of 22 feet per second. Will it reach a height of 10 feet? Identify the correct explanation for your answer.

The height h in feet of an object shot straight up with initial velocity v in feet per second is given by h 16t2 vt c where c is the initial height of the objec class=


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