Find the equation of the line tangent to the curve y = 2x³ - ex - 2 at the point (0,1) and find the equation of the line normal to the curve at that point.
a) Tangent: y = x + 1, Normal: y = -x + 1
b) Tangent: y = x - 1, Normal: y = -x - 1
c) Tangent: y = x + 1, Normal: y = -x - 1
d) Tangent: y = x - 1, Normal: y = -x + 1