What is the sum of the first six terms of the geometric series 2 − 4 8 − . . . ? Hint: cap s sub n equals start fraction a sub one left parenthesis one minus r to the power of n end power right parenthesis over one minus r end fraction comma r ≠ 1, where a1 is the first term and r is the common ratio. (1 point) S6 = −64 S6 = 42 S6 = −42 S6 = −130



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