25. In a certain species of plant, 3 leaves (L) are dominant to one leaf (1). A plant that is heterozygous for the trait is self crossed . The following phenotypes were observed: 3 leaves: 945 1 leaf: 375 a. State the null hypothesis. (1 pts) b. Create a Chi-square chart and perform the Chi square analysis. (5 pts) c. Draw a conclusion from the results. (2 pts) x²=> (observed results - expected results)² expected results 957 conf CHI-SQUARE TABLE P 2 3 Degrees of Freedom 4 5 6 7 8 0.05 3.84 5.99 7.82 9.49 11.07 12.59 14.07 15.51 0.01 6.64 9.32 11.34 13.28 15.09 16.81 18.48 20.09​