Each step in the following process has a yield of 90.0%.
CH, +4 Cl₂CCI, +4 HCI
CCI, +2 HFCCI,F₂+ 2HCI
The CCI, formed in the first step is used as a reactant in the second step.
If 4.50 mol CH, reacts, what is the total amount of HCI produced? Assume that Cl, and HF are present in excess.



Answer :