Can someone please help me with problem #13 and #14? Please show your work. This is algebra 2 by the way.

Directions:
f(x)= 1 - 6x
g(x)= x^2-4
h(x)= 2x^2-9x+2
Find each function value.

13. (h-f)(3).

14. (h o g)(5)​



Answer :

msm555

Answer:

13) [tex] (h - f)(3) = 10 [/tex]

14)[tex] (h \circ g)(5) = 695 [/tex]

Step-by-step explanation:

To find the function values, let's substitute the given values into the respective functions:

Problem 13: [tex] (h - f)(3) [/tex]

[tex] (h - f)(3) = h(3) - f(3) [/tex]

Given:

[tex] f(x) = 1 - 6x [/tex]

[tex] h(x) = 2x^2 - 9x + 2 [/tex]

Evaluate [tex] h(3) [/tex]:

[tex] h(3) = 2(3)^2 - 9(3) + 2 [/tex]

[tex] h(3) = 18 - 27 + 2 [/tex]

[tex] h(3) = -7 [/tex]

Evaluate [tex] f(3) [/tex]:

[tex] f(3) = 1 - 6(3) [/tex]

[tex] f(3) = 1 - 18 [/tex]

[tex] f(3) = -17 [/tex]

Now, find [tex] (h - f)(3) [/tex]:

[tex] (h - f)(3) = h(3) - f(3) [/tex]

[tex] = (-7) - (-17) [/tex]

[tex] = 10 [/tex]

So, [tex] (h - f)(3) = 10 [/tex].

Problem 14: [tex] (h \circ g)(5) [/tex]

[tex] (h \circ g)(5) = h(g(5)) [/tex]

Given:

[tex] g(x) = x^2 - 4 [/tex]

[tex] h(x) = 2x^2 - 9x + 2 [/tex]

Evaluate [tex] g(5) [/tex]:

[tex] g(5) = (5)^2 - 4 [/tex]

[tex] g(5) = 25 - 4 [/tex]

[tex] g(5) = 21 [/tex]

Now, find [tex] (h \circ g)(5) [/tex]:

[tex] (h \circ g)(5) = h(g(5)) [/tex]

[tex] = h(21) [/tex]

Evaluate [tex] h(21) [/tex]:

[tex] h(21) = 2(21)^2 - 9(21) + 2 [/tex]

[tex] h(21) = 882 - 189 + 2 [/tex]

[tex] h(21) = 695 [/tex]

So, [tex] (h \circ g)(5) = 695 [/tex].