An unknown mass of aluminum at 75.0°C is placed in 120.0 mL of water (d = 1 g/mL) at 23.0°C. How much aluminum (in grams) was added if the final temperature of the water and aluminum was 29.0°C? Specific heat capacity of aluminum = 0.91 J/(g·K); water = 4.18 J/(g·K). The answer is the number of grams of aluminum (just put the number, not unit