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The sum of a number and two times a smaller number is 62. Three times the bigger number exceeds the smaller number by 116.
The bigger number is
. The smaller number is
.



Answer :

lets 2 numbers are x and y

The sum of a number and two times a smaller number is 62:  x + 2y = 62Three times the bigger number exceeds the smaller number by 116: 3x - y = 116

so
x + 2y = 62 so x = 62 - 2y
3x - y = 116

substitute x = 62 - 2y into 3x - y = 116

3x - y = 116
3(62 - 2y) - y = 116
186 - 6y - y = 116
-7y = - 70
  y = 10

x = 62 - 2y = 62 - 2(10) = 42

answer
The bigger number is 42
The smaller number is 10

The bigger number is 42

The smaller number is 10

What are number?

A number is a mathematical object used to count, measure, and label. The original examples are the natural numbers 1, 2, 3, 4, and so forth. Numbers can be represented in language with number words.

According to question, The sum of a number and two times a smaller number is 62.

Three times the bigger number exceeds the smaller number by 116.

We have to find bigger number and smaller number.

Let [tex]y[/tex] be the smaller number and [tex]x[/tex] the bigger number.

We will get the following equations:

[tex]x + 2y = 62[/tex]

[tex]3x - y = 116[/tex]

⇒[tex]6x-2y=232[/tex]

After solving both equation, we will get

[tex]y=10,x=42[/tex]

Hence, we can conclude that

The bigger number is 42

The smaller number is 10

Learn more about  number here:

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