Descriptive type questions : 1. JEE DESCRIPTIVE If A+B+C = 180° then prove the following Identities ? a) sin2A+sin 2B-sin 2C = 4cos Acos Bsin C b) cos2A+ cos2B-cos2C = 1-4sin Asin Bcos C c) sinA-sinB+sinC = 4sinA/2cos B/2sin C/2. d) cosA+cos B-cosC = -1+4cosA/2cos B/2sin C/2 e) cos²A+ cos²B+cos²C = 1-2cos Acos Bcos C f) sin²A/2+sin²B/2+sin²C/2 = 1-2sinA/2sin B/2sin C/2. BHASHYAM'S 116 IMPULSE