Given ZAOE is a right angle
Prove m/BOC = 90°
Since ZAOB is a right angle, it is 90° ZAOB is supplementary to ZBOC, so mZAOB +m/BOC= 180° By the substitution property of equality,
90° +m/BOC 180° Applying the subtraction property of equality, m/BOC = 90°
What statement is missing from the proof?
OA. ZCOD and ZAOD form a linear pair.
ZAOB and ZDOC are vertical angles
O c.
ZAOB and ZBOC form a linear pair
D. ZDOA and ZBOC are vertical angles.
B.