In triangle ABC, there is a right angle at B and the length of BC is twice the length of AB. In other words, BC = 2AB.
Square DEFB is drawn inside triangle ABC so that vertex D is somewhere on AB between A and B, vertex E is somewhere on AC between A and C, vertex F is somewhere on BC between B and C, and the final vertex is at B.
square DEFB is called an inscribed square. Determine the ratio of the area of the inscribed square DEFB to the area of triangle ABC.

In triangle ABC there is a right angle at B and the length of BC is twice the length of AB In other words BC 2AB Square DEFB is drawn inside triangle ABC so tha class=