Answered

Find the length and width of a rectangle whose perimeter is 32 feet and whose area is 60 square feet. find the length of the longer and the width of the shorter side.



Answer :

sqdancefan

Answer:

  • length: 10 ft
  • width: 6 ft

Step-by-step explanation:

You want the dimensions of a rectangle with an area of 60 square feet and a perimeter of 32 feet.

Side lengths

The perimeter is twice the sum of the length and width, so that sum is ...

  32 ft/2 = 16 ft

Factors

The area is the product of the length and width, so we are looking for factors of 60 that have a sum of 16:

  60 = 60·1 = 30·2 = 20·3 = 15·4 = 12·5 = 10·6

The sums of these factor pairs are 61, 32, 23, 19, 17, 16, so the factor pair of interest is 10 and 6.

The length and width of the rectangle are 10 ft and 6 ft, respectively.

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