Practice: Determining if a Relation is a Function the Siven is not a funcr...l
since the element in the domain is repeated!
1) {(-1, 8), (0, 15), (1,-4), (2, 0)}2) {(-5,2), (5, 2), (0, -3), (3, -8)} 3) {(-2,7), (6,2), (-2,-3), (0, 9)}
it is a function
because there is not any
Points which have the
X-Coordinate and differe
y-Coordinates.
4) {(7.2), (4,-6), (2,-2). (4,-9)} 5) {(2, 3), (2, 4), (2, 5), (2.6)}
6) {(1,-4), (2,-4), (3, 4), (4-4)}