Translate the following phrase into an absolute value inequality.
The distance between 2 and 5 times a number is no less than 8.
1.|5x−2|≥8
2.|5x−2|≤8
3.|5x+2|≤8
4. |5x+2|≥8
Trey takes the angle shown, places the point of his compass on S, and draws an arc with an arbitrary radius intersecting the rays of the angle at P and R. Trey claims that as long as he draws two more arcs by placing the needle of his compass on P and then on R, drawing a ray from S through the point at which the arcs intersect, he will be able to bisect ∠S. Is Trey correct? Explain.(1 point)
1. Trey is not necessarily correct. He will need to ensure that the distance from S to P and the distance from S to R are equal.
2. Trey is correct since the initial arc was drawn with the point of the compass on S, RS=PS.
3. Trey is not necessarily correct. He will need to ensure that the compass width remains the same for each arc drawn from P and R.
4. Trey is correct. Since the compass is placed on the points P and R to draw the remaining two arcs, the ray drawn through their intersection will bisect the angle.