Answer :
To produce a 0.40 M solution of KCl from a 0.15 M solution, you must add 1.53 grams of KCl.
To solve this problem, you need to use the formula for dilution, which is:
M1V1 = M2V2
where M1 and V1 represent the concentration and volume of the starting solution, and M2 and V2 represent the concentration and volume of the final solution.
Plugging in the values from the problem, we have:
M1 = 0.15 M
V1 = 500 mL
M2 = 0.40 M
V2 = ?
Solving for V2, we get:
V2 = M1V1 / M2 = (0.15 M)(500 mL) / (0.40 M) = 375 mL
Since 1 mL of water has a mass of 1 gram, you can use the volume of the final solution to calculate the mass of KCl you need to add:
Mass of KCl = (375 mL)(1 g/mL) = 375 g
Therefore, you need to add 1.53 grams of KCl to 500 mL of a 0.15 M KCl solution to produce a 0.40 M solution.
To learn more about dilution
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