2.65 g of sodium carbonate was dissolved in water and made up to 500 ml in a standard flask. 20 ml portions of this solution required 18.50 ml of a solution of hydrochloric acid when titrated using methyl orange indicator.

calculate:
(i) the concentration of the standard sodium carbonate solution in mol/l.
(ii) the concentration of the hydrochloric acid in mol/l.

Question

03-01-2023
Chemistry

Answered

2.65 g of sodium carbonate was dissolved in water and made up to 500 ml in a standard flask. 20 ml portions of this solution required 18.50 ml of a solution of hydrochloric acid when titrated using methyl orange indicator.

calculate:
(i) the concentration of the standard sodium carbonate solution in mol/l.
(ii) the concentration of the hydrochloric acid in mol/l.

Answer :

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TNpuvvalanarendra TNpuvvalanarendra · Answer 1 · 2023-01-03T12:11:37-05:00

(i) The concentration of the standard sodium carbonate solution is 0.05 mol/l.

(ii) The concentration of the hydrochloric acid is 0.0925 mol/l.

To solve this problem, we'll need to use the formula for molarity, which is defined as the number of moles of solute per liter of solution.

First, let's find the concentration of the standard sodium carbonate solution in mol/L. We know that the solution contains 2.65 g of sodium carbonate and has a volume of 500 mL. We also know that the molar mass of sodium carbonate is 106 g/mol. We can use this information to calculate the number of moles of sodium carbonate in the solution:

2.65 g sodium carbonate / 106 g/mol = 0.025 mol sodium carbonate

The concentration of the solution in mol/L is equal to the number of moles of solute divided by the volume of the solution in liters. We can convert the volume of the solution from mL to L by dividing by 1000:

Concentration = 0.025 mol / (500 mL / 1000 mL/L) = 0.05 mol/L

Now let's find the concentration of the hydrochloric acid in mol/L. We know that 20 mL portions of the sodium carbonate solution required 18.50 mL of hydrochloric acid when titrated using a methyl orange indicator. We also know that the volume of hydrochloric acid used was 18.50 mL and the volume of the sodium carbonate solution was 20 mL.

We can use this information to calculate the concentration of the hydrochloric acid:

Concentration = (Volume of hydrochloric acid / Volume of sodium carbonate solution) * Concentration of sodium carbonate solution

= (18.50 mL / 20 mL) * 0.05 mol/L = 0.0925 mol/L

Therefore, the concentration of the standard sodium carbonate solution is 0.05 mol/L and the concentration of the hydrochloric acid is 0.0925 mol/L.

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