dispflt8553 dispflt8553

30-12-2022
Chemistry

Answered

Consider the enzyme-catalyzed reaction with Vmax=164 (μmol/L)min−1 and KM=32μmol/L. Part A If the total enzyme concentration was 6 nmol/L, how many molecules of substrate can a molecule of enzyme process in each minute? Express your answer to three significant figures kcat kcat = 2.73×10^4 min^−1. Part B Calculate kcat/KM for the enzyme reaction.

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