The angle bisectors of AABC are AV, BV, and CV. They meet at a single point V.

(In other words, V is the incenter of AABC. )

Suppose TV=18, CV=27, mZTCU=22°, and m2 SAV=32°.

Find the following measures.

Note that the figure is not drawn to scale.

B

mZSAU = 1

T

S

m 2 SBV =

V

SV = 0

А

U

Check