in a certain african population, 4 % of the population is born with sickle cell anemia (aa). calculate the percentage of individuals who enjoy the selective advantage of the sickle- cell gene?



Answer :

Percentage of heterozygote who have selected advantage of sickle cell gene is 32%.

What occurs to someone who has sickle cell anemia?

Sickle cells that obstruct organ blood flow deprive those organs of oxygen and blood. Blood oxygen levels in sickle cell anemia are also consistently low. The kidneys, liver, spleen, and other organs can all suffer damage from this lack of oxygen-rich blood, which can be fatal.

Percentage of people who have sickle cell disease(aa) = 4%

aa's frequency = p² = 4/100 = 0.04

Frequency of a particular allele = q = √0.04 = 0.2

A allele's allele frequency = p = 1-q = 1-0.2 = 0.8

Due to the short half-life of sickle-shaped RBCs, malarial parasites do not finish their reproductive life cycle, giving heterozygotes Aa a selective advantage (increased malaria resistance).

Heterozygotes with the genotype Aa in the population

2pq = 2×0.8×0.2 = 0.32

Population heterozygotes as a percentage = 0.32×100 = 32%.

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