what is the average mass of a fictitious element if it only has two naturally occurring istotopes: x and y? isotope x has a mass of 155.8 amu and isotope y has a mass of 153.7 amu while the percent abundance of isotope x is 52.45%.



Answer :

The average atomic mass of a fictitious element is 154.8  amu.

What is average atomic mass ?

The weighted average mass of the atoms in a naturally occurring sample of an element is the average atomic mass, also known as atomic weight. Unified atomic mass units (u), where 1 u is equal to precisely one-twelfth the mass of a neutral atom of carbon-12, are the standard units used to express  average masses.

The average atomic mass of any element is given by

=        [tex]\frac{atomic mass of X * percent of isotope X +mass of Y * percent of isotope Y}{percent of isotope X + percent of isotope Y}[/tex]

=​[atomic  mass of X * percent of isotope X +mass of Y * percent  of  isotope Y]/[percent of  isotope X + percent  of  isotope Y]

where  

atomic mass of  X=155.8 amu

atomic mass of  Y=153.7 amu

percent abundance of isotope X = 52.45%.

percent abundance of isotope Y = 47.55%.

average atomic mass of  fictitious element is

=[155.8 * 52.45 + 153.7 * 47.55]/{52.45 + 47.55]

= 154.80145 ≅  154.80 amu

So the average atomic mass of a fictitious element is 154.80 atomic mass unit.

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