8. 0.174 g of h2 and 1.365 g of n2 are put into a 2.83 l glass bulb at standard temperature. a) what are the partial pressures of h2 and n2 and what is the total gas pressure?



Answer :

The partial pressure of H₂ 0.69 atm is  and N₂ is 0.38 atm  the total pressure of the gas is 1.07 atm.

given that :

mass of H₂ = 0.174 g

moles of H₂ = mass / molar mass

                    = 0.174 / 2

                    = 0.087 mol

moles of  N₂  = mass / molar mass

                      = 1.365 / 28

                      = 0.048 mol

the ideal gas formula is given as :

P V = n R T

Partial pressure of H₂ = n R T / V

                                    = ( 0.087 × 0.0823 × 273) / 2.83

                                    = 0.69 atm

Partial pressure of  N₂ = n R T / V

                                      = ( 0.048 × 0.0823 × 273 ) / 2.83

                                      = 0.38 atm

The total pressure  gas = partial pressure of H₂ + partial pressure of N₂

                                       = 0.69 + 0.38

                                       = 1.07 atm

To learn more about partial pressure here

https://brainly.com/question/25410404

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