The olubility of potaium nitrate at 20°C i 250 g/L. Calculate the ma of
potaium nitrate we mut diolve in 400 ml of water for having a aturated olution
at 20°C



Answer :

The solubility of the potassium nitrate at 20 °C is 250 g /L. the mass of the potassium nitrate is 1g.

given the :

solubility of the potassium nitrate = 250 g/L

volume of the water = 400 mL = 0.4 L

the solubility of the potassium nitrate is expressed as :

solubility = (mass of potassium nitrate / volume ) × 100

250 = ( mass of potassium nitrate / 0.4 ) × 100

mass of potassium nitrate  = ( 250 × 0.4 ) / 100

mass of potassium nitrate  = 1 g

The mass  of potassium nitrate is 1 g/L.

To learn more about solubility here

https://brainly.com/question/29797075

#SPJ4

Other Questions