The solubility of the potassium nitrate at 20 °C is 250 g /L. the mass of the potassium nitrate is 1g.
given the :
solubility of the potassium nitrate = 250 g/L
volume of the water = 400 mL = 0.4 L
the solubility of the potassium nitrate is expressed as :
solubility = (mass of potassium nitrate / volume ) × 100
250 = ( mass of potassium nitrate / 0.4 ) × 100
mass of potassium nitrate = ( 250 × 0.4 ) / 100
mass of potassium nitrate = 1 g
The mass of potassium nitrate is 1 g/L.
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