Read the scenario carefully then select the correct answer A travel agency will plan tours for groups of 25 or larger. If the group contains exactly 25 people, the price is 300 per person. However, the price per person is reduced by \$10 for each additional person above 25 . You ant to find what size group will produce the largest revenue for the agency. When
x
is the number of people Ided to the 25 , the total revenue will be
R(x)=(25+x)(300−10x)
and the marginal revenue is
R ′
(x)=50
x. Once you gather this information, what will you do next?? a. Set the Revenue equal to zero. The
x
values I find are possible extrema. I substitute these values into the Marginal revenue to see which ones give me the highest value. This should be the maximum value. b. Set the Marginal Revenue to zero. The
x
values I find will be possible extrema. I substitute these values into the Revenue to see which ones give me the highest value. This should be the maximum value. c. Set the marginal revenue to zero. The
x
values I find will be possible extrema. I substitute these values back into the Marginal Revenue to see which ones give me the highest value. This should be the maximum value. d. Set the Revenue to zero. The
x
values I find will be possible extrema. I substitute these values back into the Revenue to see which ones give me the highest value. This should be the maximum value. 10. After the previous step I verify that this critical point does indeed yield the absolute maximum value by making which of the following two choices. Circle one of the choices in the table below. a. Use the
1 st derivative test. The interval on the left of the critical point should be positive when I substitute a value less than my critical point into the Revenue, indicating an increase in the Marginal Revenue. The interval on the right of the critical point should be negative when I substitute a value greater than my critical point into the Revenue, indicating a decrease in the Marginal Revenue. b. Use the 1st derivative test. The interval on the left of the critical point should be negative when I substitute a value less than my critical point into the Marginal Revenue, indicating an increase in the Revenue. The interval on the right of the critical point should be positive when I substitute a value greater than my critical point into the Marginal Revenue, indicating a decrease in the Revenue. c. Use the 1st derivative test. The interval on the left of the critical point should be negative when I substitute a value less than my critical point into the Revenue, indicating an increase in the Marginal Revenue. The interval on the right of the critical point should be positive when I substitute a value greater than my critical point into the Revenue, indicating a decrease in the Marginal Revenue. d. Use the 1st derivative test. The interval on the left of the critical point should be positive when I substitute a value less than my critical point into the Marginal Revenue, indicating an increase in the Revenue. The interval on the right of the critical point should be negative when I substitute a value greater than my critical point into the Marginal Revenue, indicating a decrease in the Revenue. e. I can check to see if the second derivative is positive, which would be concave up. This would mean there is a max. f. I can check to see if the second derivative is positive, which would be concave down. This would mean there is a max. g. I can check to see if the second derivative is negative, which would be concave up. This would mean there is a max. h. I can check to see if the second derivative is negative, which would be concave down. This would mean there is a max. i. I can check to see if the second derivative is positive, which would be concave up. This would mean there is a min. j. I can check to see if the second derivative is positive, which would be concave down. This would mean there is a min. k. I can check to see if the second derivative is negative, which would be concave up. This would mean there is a min. I. I can check to see if the second derivative is negative, which would be concave down. This would mean there is a min.