Answer :
The temperature of the gas at a pressure of 5.00 atm. is 597 °C.
Given:
Initial Pressure P1 =2.00 atm.
Initial Temperature T1 = 75 °C =384 K
Final Pressure P2 = 5.00 atm.
Final Temperature T2= ?
Ideal gas equation is given by :
P1V1/ T1 = P2V2/T2
Volume remains constant
P1/T1 = P2/T2
Calculation for Temperature T2:
P1/T1 = P2/T2
2.00 atm. / 348 K =5.00 atm. / T2
T2= 870 K = 597 °C
In chemistry, we define the temperature of a substance as the average kinetic strength of all of the atoms or molecules of that substance. No longer do all of the debris of a substance have identical kinetic strength. At any given time, the kinetic energy of the debris may be represented by means of a distribution.
Learn more about Temperature here:- brainly.com/question/2339046
#SPJ4
