When 0.55 grams of solid calcium chloride, is dissolved in 250 ml of water, the pH of the solution is 1.7.
given that :
mass of sodium chloride , CaCl₂ = 0.55 g
volume = 250 ml = 0.25 L
moles of sodium chloride = mass / molar mass
= 0.55 / 111
= 0.00495 mol
the molarity expression is given as :
Molarity = moles / volume in L
= 0.00495 / 0.25
= 0.0198 M
pH = - log (0.0198 )
= 1.7
The pH of the solution which contains the 0.55 g of sodium chloride in the water of 250 ml is 1.7.
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