Answer :
The rate at which the heptane gas diffuse under the same conditions is
12 ml/min.
Diffusion, the process resulting from the random movement of molecules with a net flow of material from areas of high concentration to areas of low concentration. A well-known example is the scent of flowers, which quickly permeates the air of a quiet room.
Calculation :
The ratio g diffusivity g two gases at the same conditions can be given by the relation
[tex]\frac{um_{1} }{um_{2}} = \sqrt\frac{MM_{2} }{MM_{1} }[/tex]
here, [tex]um_{1}[/tex] = 30 ml/min
[tex]MM_{1}[/tex] = [tex]CH_{4}[/tex] = 16 g/mol
[tex]MM_{2}[/tex] = 100g
[tex]um_{2}[/tex] = ?
Put all values,
[tex]\frac{30}{um_{2} } = \sqrt\frac{100}{16}[/tex]
[tex]um_{2}[/tex] = 12 ml/min
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