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g a certain hydroxide salt with the formula moh3 has a solubility product constant of 9.96 x 10^-36. calculate the molar solubility of this hydroxide salt in pure water



Answer :

A certain hydroxide salt with the formula M(OH)₃ has a solubility product constant of 9.96 x 10⁻³⁶. The molar solubility of this hydroxide salt in pure water is  7.7 × 10⁻¹⁰ M of  M(OH)₃  

The Ksp of M(OH)₃ = 9.96 x 10⁻³⁶

                           M(OH)₃   ⇄    M³⁺   +   3OH⁻

initial                   ---                    0        10⁻⁷

change                                     + s       +3s

at equ.                                          s          10⁻⁷ + 3s

Ksp = [M³⁺ ] [ OH⁻ ]³

9.96 x 10⁻³⁶ = (s) (10⁻⁷ + 3s)

now assume : (10⁻⁷ + 3s) ≅ 3s

9.96 x 10⁻³⁶ = (s) (3s)³

9.96 x 10⁻³⁶ = 27 s⁴

s⁴ = 9.96 x 10⁻³⁶  / 27

s = ( 0.36 × 10⁻³⁶)^1/4

s = 7.7 × 10⁻¹⁰ M of  M(OH)₃  

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