Answer :
1062.3 KJ heat is absorbed or released in the reaction of 20.0 g of nh3 with sufficient oxygen to produce no (g) and h2o (l).
The heat absorbed or released in the reaction of 20.0 g of NH3 with oxygen to produce NO and H2O depends on the specific conditions of the reaction and the enthalpy change associated with the reaction.
The general equation for the reaction of NH3 with oxygen to produce NO and H2O is:
4NH3 + 5O2 -> 4NO + 6H2O
The enthalpy change for this reaction, which is the heat absorbed or released during the reaction, can be calculated using the enthalpy changes of formation of the reactants and products. The enthalpy change of formation is the heat absorbed or released when a substance is formed from its elements in their standard states.
The enthalpy change of formation of NH3 is -46.2 kJ/mol, the enthalpy change of formation of O2 is 0 kJ/mol, the enthalpy change of formation of NO is +90.3 kJ/mol, and the enthalpy change of formation of H2O is -285.8 kJ/mol.
To calculate the enthalpy change for the reaction, we can use the following equation:
ΔH = (4 x -46.2 kJ/mol) + (5 x 0 kJ/mol) - (4 x +90.3 kJ/mol) - (6 x -285.8 kJ/mol)
This gives us an enthalpy change of -902.8 kJ/mol.
To convert this to the heat absorbed or released for 20.0 g of NH3, we need to multiply by the number of moles of NH3 used in the reaction. The molar mass of NH3 is 17.0 g/mol, so 20.0 g of NH3 is equal to
20.0 g / 17.0 g/mol = 1.18 moles of NH3.
The heat absorbed or released in the reaction of 20.0 g of NH3 with oxygen to produce NO and H2O is therefore -902.8 kJ/mol x 1.18 moles = -1062.3 kJ.
This means that the reaction absorbs 1062.3 kJ of heat from the surroundings.
To know more about oxygen please refer: https://brainly.com/question/1506082
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