Answer :
405 ml is the volume if the pressure is decreased to 0.200 atm while temperature is held constant
Initial Pressure P 1 = 0.6 atm
Final Pressure P 2 = 0.2 atm
Initial volume V 1 = 135 mL
Using Boyle's Law,
At constant temperature,
P 1 x V 1 = P 2 x V 2
0.6 atm x 135 mL = 0.2 atm x V 2
Final volume = V 2 = 0.6*135/0.2
= 405 mL
Thus if a sample of gas has a volume of 135 ml at 0.600 atm. 405 mL would be the volume if the pressure is decreased to 0.200 atm while temperature is held constant.
a sample of gas has a volume of 135 ml at 0.600 atm. what would be the volume if the pressure is decreased to 0.200 atm while temperature is held constant?
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