Aweight of 5000 N is suspended by two cables. The object is at rest. The first cable is horizontal and the second makes an angle of 143 with the first cable. Find the tension of the second cable. 5000 N 6740 N 8310N 9340N

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16-12-2022
Physics

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Aweight of 5000 N is suspended by two cables. The object is at rest. The first cable is horizontal and the second makes an angle of 143 with the first cable. Find the tension of the second cable. 5000 N 6740 N 8310N 9340N

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qwterabite qwterabite · Answer 1 · 2022-12-22T03:34:17-05:00

The tension of the second cable is 8310N

We are given the information that A weight of 5000 N is suspended by two cables. The object is at rest. The first cable is horizontal and the second makes an angle of 143 with the first cable. To find the value, we use the formula T2 = T1*cos(143°) + √T1^2-T2^2, where T1 is the tension in the first cable and T2 is the tension in the second cable. Since the object is at rest, the sum of the tensions in the two cables must equal the weight of the object, 5000N. Therefore, T1 = 5000N. We then substitute this value into the formula and solve for T2. This results in a value of 8310N for the tension in the second cable.

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