Find two consecutive odd integers such that the square of the first, added to three times the second, is 24
Showing work not necessarylet x = the 1st integer
x + 2 = the second integer
x² + 3(x + 2) = 24
x² + 3x + 6 = 24
x² + 3x - 18 = 0
(x - 3)(x + 6) = 0
x = 3 and x = -6
However, since the integer must be odd, then we only select x = 3
Therefore, the two integers are 3 and 3 + 2 = 5
3² + 3(5) = 9 + 15 = 24