(04.04 MC)

The graph of two functions is shown.

graph of f of x equals negative x squared plus x and g of x equals x minus 1

If x = −1 is a solution to f(x) = −x2 + x and g(x) = x − 1, why is it also a solution to f(x) = g(x)?

a
It is a solution to f(x) = g(x) because it is the x-intercept of the two graphs.

b
It is a solution to f(x) = g(x) because it is the y-intercept of the two graphs.

c
It is a solution to f(x) = g(x) because it is the x-coordinate where the two graphs intersect.

d
It is a solution to f(x) = g(x) because both graphs are negative at x = −1.

0404 MC The graph of two functions is shown graph of f of x equals negative x squared plus x and g of x equals x minus 1 If x 1 is a solution to fx x2 x and gx class=