When 0.4 mol of C2H5OH(l) is burned 118 kcal are liberated.
C2H5OH(l) + 3O2(g) ->2CO2(g) + 3H2O(g)
If ΔHf (CO2)= -94kcal and ΔHf (H2O)= -57.8 kcal, what is
the heat of formation of C2H5OH?