Consider the chemical equations shown here.
1. 2H₂ (g) + O₂ (g) ⇒ 2H₂O (g) | ΔH1 = -483.6 kJ/mol ΔH1 ÷ 2 = -241.8 kJ/mol
2. 3O₂ (g) ⇒ 2O₃ (g) | ΔH2 = 284.6 kJ/mol ΑH2 ÷ 2 = 142.3 kJ/mol
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What is the overall enthalpy of reaction for the equation shown below?
3H₂ (g) + O₃ (g) ⇒ 3H₂O (g)