n a certain wilderness area 1.4 mountain lions are seen each year, on average. what is the probability that in a given year exactly two mountain lions will be seen in this wilderness area? (assume that sightings are independent from each other and that the probability of seeing a mountain lion stays constant.)



Answer :

Therefore  ,the probability that in a given year exactly two mountain lions will be seen in this wilderness area is P =0.2417.

How does probability work?

Probabilities can be stated as proportions with a range of 0 to 1, or as percentages with a range of 0% to 100%. When an event has a probability of 0, it has no possibility of happening, whereas when it has a probability of 1, it is almost certain to happen. When an event has a probability of 0.45 (45%), there are 45 out of 100 chances that it will occur.

Here,

λ=1.2

=> P(X =x) = [tex]\frac{e^{-\lambda} * \lambda^{x} }{x!}[/tex]

=> P(X=2) = [tex]\frac{e^{-1.4} * 1.4^{2} }{2!}[/tex]

=> P(X=2) = 0.2466 * 1.96 /2

=>P(X=2) = 0.2417

Therefore  ,the probability that in a given year exactly two mountain lions will be seen in this wilderness area is P =0.2417.

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