The chemical equation for the combustion of pentaborane is as follows:

2 B5H9 + 12 O2 => 5 B2O3 + 9 H2O

The energies of the different chemicals are as follows:

2 B5H9 is equal to 146.4 kJ/mol

12 O2 is equal to 0 kJ/mol

5 B2O3 is equal to -6363.85 kJ/mol

9 H2O is equal to -2176.38 kJ/mol



Calculate the energy difference between the products and reactants and determine if the reaction is exothermic or endothermic