Answer :
Simple harmonic motion with a period of 0.100 s is carried out by a 240 g block that is fastened to a horizontal spring.the spring's force constant is 947.4 N/m, and the motion's amplitude is 0.00211 m.
Let:
m=240g,T=0.100s,E=1.00J
ω=2π/T
=2π/0.1=62.83 rad/s
(a) k=mω²=(0.240kg)(62.83 rad/s)²=947.4 N/m
(b) E=kA²/2
A=√(2E/k)=√(2*1.0 J/947.4 N/m)
A=0.00211m
Simple harmonic motion is the repetitive movement back and forth through an equilibrium, or central, position in physics where the maximum displacement on one side of the position is equal to the maximum displacement on the other. Each entire vibration has a constant duration between them. The motion is always caused by a force that is directly proportionate to the distance from the equilibrium position and is always directed toward it. In other words, the equation F = kx, where F is the force, x is the displacement, and k is a constant The relationship is known as Hooke's law.
The oscillation of a mass attached to a vertical spring with the other end fixed in a ceiling is one particular instance of a simple harmonic oscillator.
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