Two balls of clay known masses hang from the ceiling on masslessstrings of equal length. They barely touch when both hang atrest. One ball is pulled back until its string is45o, the released. It swings down, collides withthe second ball, and they stick together. To determine theangle to which the balls wing to the opposite side, you need toinvoke:
A. Conservation of momentum
B. Conservation of mechanicalenergy
C. Both conservation of momentum andconservation of mechanical energy
D. Either, but not both.
E. These principles alone are not sufficientto find the angle

Question

09-12-2022
Physics

Answered

Two balls of clay known masses hang from the ceiling on masslessstrings of equal length. They barely touch when both hang atrest. One ball is pulled back until its string is45o, the released. It swings down, collides withthe second ball, and they stick together. To determine theangle to which the balls wing to the opposite side, you need toinvoke:
A. Conservation of momentum
B. Conservation of mechanicalenergy
C. Both conservation of momentum andconservation of mechanical energy
D. Either, but not both.
E. These principles alone are not sufficientto find the angle

Answer :

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saishreechandan907 saishreechandan907 · Answer 1 · 2022-12-17T04:07:28-05:00

The combination of momentum conservation and mechanical energy conservation yields the letter C.

You need:

1.Conservation of energy to calculate the velocity of the firstball of clay by the time it descends:

mgh=1/2mu2

[calculate h by using h=L(1-cos45)]

2.Conservation of momentum to find out the final velocity of theballs of clay using:

m1u1+m2u2=(m1+m2)v ---note:u2=0

3.Conservation of energy to calculate the max height the balls ofclay will go by using:

1/2(m1+m2)v2=mgh

Once you have h,

h=L(1-cosθ), solve for θ

In Newtonian physics, an object's mass and velocity are combined to form momentum, more precisely linear momentum or translational momentum. It has both a magnitude and a direction, making it a vector quantity. If an item has mass (m) and velocity (v), both of which are vector quantities, then it has momentum (p).

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