you place a small air cart on a 3.00 m air track and set it into motion with a speed of 0.70 m/s. due to very good elastic bumpers at each end of the track, the cart oscillates back and forth between the two ends of the track with essentially no loss in energy. determine the period and the frequency for this motion. you may assume that the length of the cart is negligible compared to the length of the track.



Answer :

The motion has an 8.57 second period, and its frequency is 0.11 Hz. You can suppose that the distance between the cart and the track is little.

Period= T = 2*3/0.7 = 8.57 sec

The period of the motion is 8.57seconds

 freq = f = 1/T = 1 /8.57 = 0.11 Hz

The frequency of the motion is0.11Hz

The number of waves that pass a fixed point in a unit of time is known as frequency in physics. It is also the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. When a body in periodic motion moves through a series of events or locations before returning to its initial state, it is said to have experienced one cycle or one vibration. A simple harmonic motion is also seen under angular velocity.

If one cycle or vibration takes half a second to complete, the frequency is two per second; if it takes a full hour, the frequency is one hundred per hour. Frequency is often equal to the reciprocal of the period, or time interval; for example, frequency = 1/period = 1. (time interval).

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