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in fig. 11-37, a small, solid, uniform ball is to be shot from point p so that it rolls smoothly along a horizontal path, up along a ramp, and onto a plateau.then it leaves the plateau horizontally to land on a game board, at a horizontal distance d from the right edge of the plateau. the vertical heights are h1 ! 5.00 cm and h2 ! 1.60 cm. with what speed must the ball be shot at point p for it to land at d ! 6.00 cm?



Answer :

The ball must be fired at point p with a speed of 6.635 m/s in order for it to settle at a distance of 6 cm.

Due to it,

Height h1 equals 5 cm

h2 = 1.6 cm tall

Distance d = 6 cm

We are aware that t = (h2/g2) = (1.6*)/9.8 = 0.57 s.

We are aware that distance is simply speed times time.

The expression may be written as d = V1* t V1 = d/t = 6/0.57 = 10.52 m/s based on the aforementioned assertion.

According to the work energy theory, mg(h1-h2) = 1/2* m* V12 - 1/2* m* V22.

When "m" is removed from both sides, 1/2* V12 - 1/2* V22 = g(h1 - h2) 9.8 (5 - 1.6) = 1/2* 10.522 - 1/2* V22 33.32 = 1/2(10.522 - V22) (10.522 - V22) = 66.64 V22 = 44.03 V2 = 6.635 m/s

In light of this, the recommended ball speed is 6.635 m/s.

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