Answer :
A block of mass 3 kg slides down an inclined plane at an angle of p with a massless tether attached to a pulley with mass 1 kg and radius 0.5 m at the top of the incline. The acceleration of the block is a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2).
Formula of acceleration = a bar = (v - v0)/t = delta v / delta t
a bar = average acceleration
v = final velocity
v0 = starting velocity
t = elapsed time
After solving by the formula we get, a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2).
Acceleration refers to the rate at which an object's velocity with respect to time varies. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it. According to Newton's Second Law, the amount of an object's acceleration is the combined result of two causes: According to the materials used to make the object, the magnitude of the net balance of all external forces acting on it is inversely proportional to its mass, but the magnitude of the net resulting force is directly proportional to the net force.
We are aware that the angle = 45°, the block's mass m1 is 3 kg, and the pulley's mass m2 is 1 kg.
Pulley radius is 0.5 meters, and its coefficient of friction is 0.4.
Four forces are at work on the mass-m1 block:
Weight is represented by m1g, normal response force by N, tension by T, and frictional force by f.
After solving we get acceleration = a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2)
To know more about acceleration please refer: https://brainly.com/question/3046924
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