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Three boxes are pushed on a floor with a constant force of magnitude F applied to box A. The boxes move to the right with an acceleration of 1.5 m/s2. The coefficient of kinetic friction between the bottom of a block and the floor is 0.4. 2.0 kg B 1.0 kg 3.0 kg What is the magnitude of the force that block B applies to block C? A) 1.5 N B) 4.5 N C) 7.3N D) 16.3 N E) There is not enough information to tell.



Answer :

the magnitude of the force that block B applies to block C is 16.3  N .

Calculation :

frictional force of this combination = 0.4*9.8(Ma + Mb)

                                                         = 0.4*9.8*3

                                                       F(ab)= 11.76 N

F(AB) = Net force of this combination = 3*1.5 = 4.5 N

since block ' c ' is also moving with the same acceleration ,

Net force on C by B = F - (F(ab) +F(AB) )

                                  = 32.52 - (11.76 + 4.5)

                                  = 32.52 - 16.26

                                   = 16.3 N

the word "force" has a precise meaning. At this level it is appropriate to describe the force as pushing or pulling. A force does not contain or "have within" an object. A force is applied from one object to another. The idea of ​​force is not limited to animate and inanimate objects.

Learn more about force here : https://brainly.com/question/12785175

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