Evanbus
Answered

Given the reaction below, how many moles of Sodium chloride (NaCl) would be made if you started with 9.6 moles of Zinc
(II) Chloride (ZnCl₂)?
2 Na + ZnCl₂ → 2 NaCl + Zn
A)9.6 moles NaCl
B) 4.8 moles NaCl
C)19.2 moles NaCl
D)2.4 moles NaCl