a) if 13 cards are randomly selected from a standard 52-card deck, must at least 2 be of the same denomination (2, 3, 4, , j, q, k, a)? why? (select all that apply.) yes. for example, six hearts: 2, 3, 4, 5, 6, 7, and seven diamonds: 2, 3, 4, 5, 6, 7, 8, could be selected. six of these are of the same denomination. no. for example, thirteen hearts could be selected: 2, 3, 4, 5, 6, 7, 8, 9, 10, j, q, k, a. no two of these are of the same denomination. no. for example, thirteen hearts could be selected: 2, 3, 4, 5, 6, 7, 8, 9, 10, j, q, k, a. at least two of these are of the same denomination. no. for example, the 2, 4, 6 of hearts, the 5, 10, k of diamonds, the 8, 9, j, a of clubs, and the 3, 7, q of spades have no two cards that are of the same denomination. no. for example, six hearts: 2, 3, 4, 5, 6, 7, and seven diamonds: 2, 3, 4, 5, 6, 7, 8, could be selected. six of these are of the same denomination. (b) if 20 cards are randomly selected from a standard 52-card deck, must at least 2 be of the same denomination (2, 3, 4, ..., j, q, k, a)? why? yes . let a be the set of 20 cards selected from the 52-card deck, and let b be the 4 different denominations of cards in the deck. if we construct a function from a to b, then by the zero product principle, the function must be onto . therefore, it is possible to randomly select 20 cards with no