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For the function ƒ(x) = 5 (x³ – 6), find ƒ−¹(x).
○ ƒ˜¹(x) = (²16) ³
○ f−¹(x) = 2³+6
○ ƒ˜¹(x) = ( ² + 6) ³
○ ƒ−¹(x) = (x+6)³
5
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