an architect is making a floor plan for a rectangular gymnasium. if the gymnasium is 80 feet long and 60 feet wide, what will the distance be between opposite corners?



Answer :

In the gym, there are 100 feet between the opposing corners.

Given,

The length of the rectangular gymnasium = 80 feet

The width of the rectangular gymnasium = 60 feet

We have to find the distance between opposite corners of the gymnasium;

Here,

The distance between opposite corners of the gymnasium is the diagonal of the rectangle;

Diagonal of rectangle = [tex]\sqrt{width^{2} + length^{2} }[/tex]

Then,

Diagonal = [tex]\sqrt{80^{2} +60^{2} }[/tex]

Diagonal = [tex]\sqrt{6400+3600}[/tex]

Diagonal = √10000

Diagonal = 100 feet

That is,

The distance between the opposite corners if the gymnasium is 100 feet.

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